Lists and Iteration Unit 3 Sections 8 and 10
Lists and Iteration Lesson
fruits = ["apple", "grape", "strawberry"]
print (fruits)
const fruits = ["apple", "grape", "strawberry"];
fruits ← [apple, grape, strawberry]
brands = ["nike", "adidas", "underarmour"] #string
numbers = [1, 2, 3, 4, 5] #integer
truefalse = [True, False, True] #boolean
fruits = ["apple", "grape", "strawberry"]
index = 1
print (fruits[index])
Methods in Lists
| Method | Definition | Example |
|---|---|---|
| append() | adds element to the end of the list | fruits.append("watermelon") |
| index() | returns the index of the first element with the specified value | fruits.index("apple") |
| insert() | adds element at given position | fruits.insert(1, "watermelon") |
| remove() | removes the first item with the specified value | fruits.remove("strawberry") |
| reverse() | reverses the list order | fruits.reverse() |
| sort() | sorts the list | fruits.sort() |
| count() | returns the amount of elements with the specified value | fruits.count("apple") |
| copy() | returns a copy of the list | fruits.copy() |
| clear() | removes the elements from the list | fruits.clear() |
sports = ["football", "soccer", "baseball", "basketball"]
# change the value "soccer" to "hockey"
sports.remove("soccer")
sports.insert(1, "hockey")
print (sports)
sports = ["football", "soccer", "baseball", "basketball"]
# add "golf" as the 3rd element in the list
sports.insert(2, "golf")
print (sports)
Try this
- Determine the output of the code segment
The psuedocode iterates through the list words so for each stirng in words. If the length of the word is equal to 3 than it will remove the word from the list. If the length of the string is not equal to three it will incrment the index variable. The program will print the words in the list that are not three letters ps images don't dispaly on wget and link doesn't seem to dierect to blog
print("alpha")
print("bravo")
print("charlie")
print("delta")
print("echo")
print("foxtrot")
print("golf")
print("hotel")
print("india")
print("juliett")
print("kilo")
print("lima")
print("mike")
print("november")
print("oscar")
print("papa")
print("quebec")
print("romeo")
print("sierra")
print("tango")
print("uniform")
print("victor")
print("whiskey")
print("x-ray")
print("yankee")
print("zulu")
#please help me
Coding all of these individually takes a lot of unnecessary time, how can we shorten this time?
Iteration
Iteration is the repetition of a process or utterance applied to the result or taken from a previous statement. There's a lot of types of iteration though, what to use? How do we apply iteration to lists?
Some methods include using a "for loop", using a "for loop and range()", using a "while loop", and using comprehension
Lists, tuples, dictionaries, and sets are iterable objects. They are the 'containers' that store the data to iterate.
Each of these containers are able to iterate with the iter() command.
There are 2 types of iteration:definite and indefinite. Definite iteration clarifies how many times the loop is going to run, while indefinite specifies a condition that must be met
for variable in iterable:
statement()
a = ['alpha', 'bravo', 'charlie']
itr = iter(a)
print(next(itr))
print(next(itr))
print(next(itr))
list = ["Alpha", "Bravo", "Charlie", "Delta", "Echo", "Foxtrot", "Golf", "Hotel", "India", "Juliett", "Kilo", "Lima", "Mike", "November", "Oscar", "Papa", "Quebec", "Romeo", "Sierra", "Tango", "Uniform", "Victor", "Whiskey", "X-ray", "Yankee", "Zulu"]
# using a for loop
for i in list:
#for item in the list, print the item
print(i)
list = ["Alpha", "Bravo", "Charlie", "Delta", "Echo", "Foxtrot", "Golf", "Hotel", "India", "Juliett", "Kilo", "Lima", "Mike", "November", "Oscar", "Papa", "Quebec", "Romeo", "Sierra", "Tango", "Uniform", "Victor", "Whiskey", "X-ray", "Yankee", "Zulu"]
# Taking the length of the list
lengthList = len(list)
# Iteration using the amount of items in the list
for i in range(lengthList):
print(list[i])
list = ["Alpha", "Bravo", "Charlie", "Delta", "Echo", "Foxtrot", "Golf", "Hotel", "India", "Juliett", "Kilo", "Lima", "Mike", "November", "Oscar", "Papa", "Quebec", "Romeo", "Sierra", "Tango", "Uniform", "Victor", "Whiskey", "X-ray", "Yankee", "Zulu"]
# Once again, taking the length of the list
lengthList = len(list)
# Setting the variable we are going to use as 0
i=0
# Iteration using the while loop
# Argument saying WHILE a certain variable is a certain condition, the code should run
while i < lengthList:
print(list[i])
i += 1
x = range(5)
for n in x:
print(n)
codes = ["alfa", "bravo", "charlie", "delta", "echo", "foxtrot", "golf", "hotel", "india", "juliett", "kilo", "lima", "mike", "november", "oscar", "papa", "quebec", "romeo", "sierra", "tango", "uniform", "victor", "whiskey", "xray", "yankee", "zulu"]
def Nato(codes):
phrases = []
rsp = input("Enter a word you want to convert into NATO code: ")
solve_rsp = rsp.lower().strip()
for letter in solve_rsp:
for code in codes:
if code[0] == letter:
phrases.append(code)
for phrase in phrases:
print(phrase)
Nato(codes)
keypad = [[1, 2, 3], [4, 5, 6], [7, 8, 9], [" ", 0, " "]]
Conventially 2D arrays are written like below. This is because 2D arrays are meant to be read in 2 dimensions (hence the name). Writing them like below makes them easier to visualize and understand.
keypad = [[1, 2, 3],
[4, 5, 6],
[7, 8, 9],
[" ", 0, " "]]
def print_matrix1(matrix):
for i in range(len(matrix)): # outer for loop. This runs on i which represents the row. range(len(matrix)) is in order to iterate through the length of the matrix
for j in range(len(matrix[i])): # inner for loop. This runs on the length of the i'th row in the matrix (j changes for each row with a different length)
print(matrix[i][j], end=" ") # [i][j] is the 2D location of that value in the matrix, kinda like a coordinate pair. [i] iterates to the specific row and [j] iterates to the specific value in the row. end=" " changes the end value to space, not a new line.
print() # prints extra line. this is in the outer loop, not the inner loop, because it only wants to print a new line for each row
print("Raw matrix (list of lists): ")
print(keypad)
print("Matrix printed using nested for loop iteration:")
print_matrix1(keypad)
print()
def print_matrix2(matrix):
for row in matrix: # Iterates through each "row" of matrix. Row is a dummy variable, it could technically be anything. It iterates through each value of matrix and each value is it's own list. in this syntax the list is stored in "row".
for col in row: # Iterates through each value in row. Again col, column, is a dummy variable. Each value in row is stored in col.
print(col, end=" ") # Same as 1
print() # Same as 1
print_matrix2(keypad)
fruit = ["apples", "bananas", "grapes"]
print(fruit)
print(*fruit) # Python built in function: "*". Figure out what it does
def print_matrix3(matrix):
code = "your code goes here"
# Don't have to do one
keypad = [[1, 2, 3],
[4, 5, 6],
[7, 8, 9],
[" ", 0, " "]]
def print_matrix4(keypad):
iterations = iter(keypad)
while True:
try:
row = next(iterations)
for column in row:
print(column, end = " ")
print()
except StopIteration:
break
print_matrix4(keypad)
Print what month you were born and how old you are by iterating through the keyboard (don't just write a string).
keyboard = [["`", "1", "2", "3", "4", "5", "6", "7", "8", "9", "0", "-", "="],
["Q", "W", "E", "R", "T", "Y", "U", "I", "O", "P", "[", "]"],
["A", "S", "D", "F", "G", "H", "J", "K", "L", ";", "'"],
["Z", "X", "C", "V", "B", "N", "M", ",", ".", "/"]]
def printer(keyboard):
rsp = input("Month: ")
rsp2 = input("Age: ")
solve_rsp = "" + str(rsp.upper().strip())
solve_rsp2 = "" + str(rsp2).strip().upper()
for letter in solve_rsp:
if any(letter in row for row in keyboard):
print(letter)
for row in keyboard:
if letter in row == False:
row[row.index(letter)] = " "
for letter in solve_rsp2:
if any(letter in row for row in keyboard):
print(letter)
for row in keyboard:
if letter in row == False:
row[row.index(letter)] = " "
printer(keyboard)
Challenge also homework
Change all of the letters that you DIDN'T print above to spaces, " ", and then print the full keyboard. (the things you did print should remain in the same spot)
Alternative Challenge: If you would prefer, animate it using some form of delay so it flashes one of your letters at a time on the board in order and repeats. (this one may be slightly more intuitive)
DO NOT HARD CODE THIS. Don't make it harder on yourself, iterate through, make it abstract so it can be used dynamically. You should be able to input any string and your code should work.
keyboard = [["`", "1", "2", "3", "4", "5", "6", "7", "8", "9", "0", "-", "="],
["Q", "W", "E", "R", "T", "Y", "U", "I", "O", "P", "[", "]"],
["A", "S", "D", "F", "G", "H", "J", "K", "L", ";", "'"],
["Z", "X", "C", "V", "B", "N", "M", ",", ".", "/"]]
def printer(keyboard):
rsp = input("Month: ")
rsp2 = input("Age: ")
solve_rsp = "" + str(rsp.upper().strip())
solve_rsp2 = "" + str(rsp2).strip().upper()
for letter in solve_rsp:
if any(letter in row for row in keyboard):
# print(letter)
for row in keyboard:
if letter in row:
row[row.index(letter)] = " "
for letter in solve_rsp2:
if any(letter in row for row in keyboard):
# print(letter)
for row in keyboard:
if letter in row:
row[row.index(letter)] = " "
for row in keyboard:
print(" ".join(row))
printer(keyboard)
If you get stuck you can just make a picture with an array and print it (I will grade based on how good it looks)
I do expect an attempt so write some code to show you tried the challenge.